Hi I'm stuck on this question. Solve the equation logx8 + logx4 = 5. Thanks in advance
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First, simplify the LHS using $\displaystyle \displaystyle \log{a} + \log{b} = \log{(ab)}$...
Originally Posted by HighlyFlammable Hi I'm stuck on this question. Solve the equation logx8 + logx4 = 5. Thanks in advance When stuck, do the obvious. The obvious thing to do in this case is apply a basic log rule to get $\displaystyle \log_x(32) = 5$, from which it follows that $\displaystyle x^5 = 32$. It ought to be simple to get x from here.
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