Thread: Find the domain and range of the function

A isosceles triangel has the perimeter 10 cm. Signb for the base and s for the sides.
Decide the function's domain and range. According to the key the answers should be:
D:0<s<5
V: 0<v<10.

How can these answers be possible? If the base are 9 cm, then the two sides of the triangel have to be 0.5 cm each and then they will not form a triangel. Can you please explain? Thank you in advance.

b = 10 -2s

since b>0
10-2s>0
s<5
then
D:0<s<5
V: 0<v<10.

if b=9
then s=0.5, this forms a triangle, why wouldn't it I'm confused??

Originally Posted by Anna55

A isosceles triangel has the perimeter 10 cm. Signb for the base and s for the sides.
Decide the function's domain and range. According to the key the answers should be:
D:0<s<5
V: 0<v<10.

How can these answers be possible? If the base are 9 cm, then the two sides of the triangel have to be 0.5 cm each and then they will not form a triangel. Can you please explain? Thank you in advance.

You are correct. There is a formula called the "Triangle Inequality." I won't state it, but the content is that the sum of any two sides of a triangle is greater than the third side. In your case the pertinent inequality is that the sum of the sides of the triangle has to be greater than the size of the base: 2s > b. Along with that you have b + 2s = 10. Thus, for example, b = 10 - 2s and 2s > b means that 2s > 10 - 2s.

Can you finish from here? (You can make a similar solution for b by solving the b + 2s = 10 equation for s and sticking that into the inequality.)

-Dan

Originally Posted by Goku

if b=9
then s=0.5, this forms a triangle, why wouldn't it I'm confused??

Have you tried to sketch this? The two sides s do not meet at a vertex.

-Dan

Should I continue like this:

2s>10-2s
4s>10
s>2.5

Originally Posted by Anna55

Should I continue like this:

2s>10-2s
4s>10
s>2.5

Yup! Now do the same for b.

-Dan