Hello,
Can a math genious please answer this question? the answer should be 2y^-1, and please show me the working...
Thanks
here is the question:
16y^10 * 4y^-4 (divided by) 32y^7
A better idea is for you to try to answer this question, post your working and where you are stuck. Then you might get some help - we won't do your work for you.
Same as 16 * 4 * y^10 * y^-4 ; so 64y^6 ; continue...
okay....
so 64y^6 is equivelent to 2y^36,
2y^36 / 32y^7 = 2y^36 / 2y^35 which gives 2y^(36-35) = 2y^1
hehe that was close! ...... can anyone please tell me where I went wrong?
thanks