Good start.

To factor this won't be easy. To start with, you have a to consider.

This means you could have something of the form (3x+...)(2x+...) or you could have something of the form (6x+...)(x+...) as either will generate a 6x^2 when expanded.

The way to do this is to write out the factors of 6:

2,3

1,6

And write out the factors of 2:

1,2

And find combinations that make 13 by multiplying pairs of numbers and adding them. It's basically trial and error here.

Starting with '2,3' and '1,2':

2 x 1 + 3 x 2 = 8

2 x 2 + 3 x 1 = 7

Neither combination is going to work. Note that 2 x 3 + 1 x 2 is not a combination to consider.

So it must be from 1,6 and 1,2

1 x 6 + 1 x 2 = 8

1 x 1 + 6 x 2 = 13

So there's the combination we need. Then you need to think about the correct arrangements. You need to multiply 6 and 2, so they need to be in opposing brackets. This means the only possible result is:

(x+2)(6x+1)