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Math Help - tranpose issue 3

  1. #1
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    tranpose issue 3

    Hi;
    I need to take the sqrt of both sides to find y. y^2 = a^2w^2 - v^2 / w^2

    Ok got that and it becomes y = sqrt(a^2w^2 - v^2) / w.

    why has the denominator been reduces to w and not the numerator to aw -v.

    Thanks.
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  2. #2
    MHF Contributor Unknown008's Avatar
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    This is because

    a^2w^2 - v^2 \neq (aw-v)^2

    If you had (aw-v)^2 in the numerator, then you would be able to put aw - v
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  3. #3
    A Plied Mathematician
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    Also, don't forget the dual sign possibilities:

    y = \pm\sqrt{a^2w^2 - v^2} / w.
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  4. #4
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    What I thought those two things would be equal please elaborate
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  5. #5
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    Oh think I just got it parenthesis done first of course
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