Hi; I need to take the sqrt of both sides to find y. y^2 = a^2w^2 - v^2 / w^2 Ok got that and it becomes y = sqrt(a^2w^2 - v^2) / w. why has the denominator been reduces to w and not the numerator to aw -v. Thanks.
Follow Math Help Forum on Facebook and Google+
This is because $\displaystyle a^2w^2 - v^2 \neq (aw-v)^2$ If you had $\displaystyle (aw-v)^2$ in the numerator, then you would be able to put aw - v
Also, don't forget the dual sign possibilities: $\displaystyle y = \pm\sqrt{a^2w^2 - v^2} / w.$
What I thought those two things would be equal please elaborate
Oh think I just got it parenthesis done first of course
View Tag Cloud