4y=8x^2+16 What is the equation of the axis of symmetry?
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Originally Posted by monicafam 4y=8x^2+16 What is the equation of the axis of symmetry? This is an upward/downward opening parabola so the form is $\displaystyle y = a(x - h)^2 + k$ where (h, k) is the vertex point. This implies that the axis of symmetry is the line x = h. Does this help? -Dan
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