4y=8x^2+16

What is the equation of the axis of symmetry?

2. Originally Posted by monicafam
4y=8x^2+16

What is the equation of the axis of symmetry?
This is an upward/downward opening parabola so the form is
$y = a(x - h)^2 + k$
where (h, k) is the vertex point. This implies that the axis of symmetry is the line x = h. Does this help?

-Dan