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Math Help - transpose formula problem 2

  1. #1
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    transpose formula problem 2

    Hi All;
    please look at question 19 I think I'm handling the denominator wrong
    all In want to know is how to handle it.


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  2. #2
    Super Member Quacky's Avatar
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    Q=C_dA_o\sqrt{\frac{2g\Delta h}{1-A_o^2/A_p^2}}

    This will be fun...

    \frac{Q}{C_d}=A_o\sqrt{\frac{2g\Delta h}{1-A_o^2/A_p^2}}

    (\frac{Q}{C_d})^2=A_o^2\times \frac{2g\Delta h}{1-A_o^2/A_p^2}

    (\frac{Q}{C_d})^2(1-A_o^2/A_p^2)=A_o^2\times{2g\Delta h}

    (\frac{Q}{C_d})^2(A_p^2-A_o^2)=A_o^2\times{2g\Delta h}A_p^2

    You'll certainly have to check my work for mistakes here, but if it's alright until this point (which is a relatively risky assumption, so don't make it!) then you should be alright to proceed? As I said, check through what I've done!
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  3. #3
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    The first thing I did was q / cda0 I take it thats wrong advise please.
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  4. #4
    Super Member Quacky's Avatar
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    Quote Originally Posted by anthonye View Post
    The first thing I did was q / cda0 I take it thats wrong advise please.
    The issue with doing that is that you need to isolate A_o terms. It isn't necessarily wrong, but you need to remove it from the denominator at a later stage if you do this, which is why I tried to avoid it.
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  5. #5
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    Any ideas where I can get help with transposing formula ie websites/books etc...

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