# Thread: transpose formula problem 2

1. ## transpose formula problem 2

Hi All;
please look at question 19 I think I'm handling the denominator wrong
all In want to know is how to handle it.

Thanks.

2. $Q=C_dA_o\sqrt{\frac{2g\Delta h}{1-A_o^2/A_p^2}}$

This will be fun...

$\frac{Q}{C_d}=A_o\sqrt{\frac{2g\Delta h}{1-A_o^2/A_p^2}}$

$(\frac{Q}{C_d})^2=A_o^2\times \frac{2g\Delta h}{1-A_o^2/A_p^2}$

$(\frac{Q}{C_d})^2(1-A_o^2/A_p^2)=A_o^2\times{2g\Delta h}$

$(\frac{Q}{C_d})^2(A_p^2-A_o^2)=A_o^2\times{2g\Delta h}A_p^2$

You'll certainly have to check my work for mistakes here, but if it's alright until this point (which is a relatively risky assumption, so don't make it!) then you should be alright to proceed? As I said, check through what I've done!

3. The first thing I did was q / cda0 I take it thats wrong advise please.

4. Originally Posted by anthonye
The first thing I did was q / cda0 I take it thats wrong advise please.
The issue with doing that is that you need to isolate $A_o$ terms. It isn't necessarily wrong, but you need to remove it from the denominator at a later stage if you do this, which is why I tried to avoid it.

5. Any ideas where I can get help with transposing formula ie websites/books etc...

Thanks.