Just seem to be struggling to understand what I am missing here?
I have;
x - 8 = 3x + 20
7
This is what I have done to try and find the value for x
7(x - 8) = 7(3x + 20)
7
56 - 7x = 3x + 20
-7x -3x = 20 - 56
-10x = -36
-10 -10
x = 3.6
Substitute value into x
3.6 - 8 = 3 x 3.6 + 20
7
-4.4 = 4.4
My problem to me is that -4.4 is not equal to 4.4?
The equation should not have two routes?
Please advise if there is an alterative technique to solve this type of problem?
P.S. the 7 above (denominator) should be divided by the numberators on the RHS of the equals sign. This software program seens to move the integer to the LHS
Sorry the equation you wrote is the wrong way round. The way I presented it was incorrectly positioned on this forum because the forum moves all intergers placed as denominators to the far left hand side for some reason?
I'll do it again;
x - 8 is on the left hand side and 3x + 20 divided by 7 is on the right hand side.
so x - 8 = 3x + 20 / 7.
multiplying both sides of the equation by 7 gives;
7(x - 8) = 3x + 20 multiply out the LHS.
7x - 56 = 3x + 20 Move the -56 to the RHS
7x = 3x + 20 + 56 Now move the 3x to the LHS
7x - 3x = 76 Subtract LHS
4x = 76 Divide both sides by 4
x = 19
The original equation; x - 8 = 3x + 20 / 7
Putting in the x value; 19 - 8 = 3 \cdot x + 20 / 7
the like values are; 11 = 11
Whatever the reason I couldn't see it before is just a state of mind?
Thanks for your help.