Alright I'm sure I'm posting this in the right area if not I am truly sorry. So I have come across a problem that me and my brother have been trying to solve for a while and cannot figure it out would love some help. The problem is:
In a baseball stadium, there are three types of seats available. Box seats are $9, Reserved seats are $6, and lawn seats are $4. The stadium capacity is 3900. If all seats are sold, the total revenue to the club is $24,600. If one half of the box seats sold, one half of the reserved seats sold, and all the lawn seats are sold, the total revenue is $15,420. How many of each kind of seat are there?
I been trying for litterly 2 hours and I can't seem to figure it out. I've tryed making a System of linear equations in 3 variables and I can't figure it out. Any help would be awesome.
Thanks in advance guys!!
b denote the number of boxed seats,
r denote the number of reserved seats,
l denote the number of lawn seats.
Then you can set up a system of simultaneous equations:
2. The solution of this system of equations is: (b, r, l) = (1980, -300, 2280)
But I can't imagine -300 seats. Must be quite a big hole in the stadium.
EDIT: Sorry I made a typo. The system of equations I set up has a unique solution