Thread: Percentage Equation help.

An elastic is stretched by 86% to a length of 5.8 m. Calculate the original length

do i use;

increase% = increase/original length?

im stumped no idea where to go

sorry if in wrong forum i looked around to see where it would fit

Given the original length is 100% then

186% of x = 5.8, solve for x.

Does that work for your question?

Originally Posted by pickslides

Given the original length is 100% then

186% of x = 5.8, solve for x.

Does that work for your question?

i do think that works yes ty sir

That's the way I would think of doing it.