Originally Posted by
gary223 Assuming a 8Bit number system, use the 2's complement method to perform the following arithemetic. Verify your anwsers, showing all workings.

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Hello,
I assume that you know how to convert a number of decimal system in a binary number. Code:
113 =======> 01110001 [a]
10
98 =======> 01100010 [b]
10
98 =======> 10011101 [c]
10
+ 00000001 [d]

100001111 [e]
[a] 113 converted into binary number
[b] 98 converted into binary number
[c] change every digit. The first digit correspond to the sign: 0 means +, 1 means .
[d] add 1
[e] now add [a], [c],[d]. You have to use a carrybit which is always set to 1 if the sum of three digits is 2 or 3.
[e] the result are the last 8 digits
Convert the dual number 00001111 ==> 15
Seems to be the right result.