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Math Help - rearranging formula q

  1. #1
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    rearranging formula q

    Hi everybody, can somebody tell me were I'm going wrong, this is driving me mad

    Make p the subject


    =1

    I get

    =p

    Which apparently is incorrect. I'd love to show you the steps I took, but this is my first ever post and I'm really struggling with the latex workaround.
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  2. #2
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    Im wont try and diagnose your mistake without seeing your working. My attempt:

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  3. #3
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    Hmmm, I get what you've done, but the answer the book gives is



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  4. #4
    Behold, the power of SARDINES!
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    Quote Originally Posted by jharrisbr8 View Post
    Hmmm, I get what you've done, but the answer the book gives is



    The answers are equivalent if

    q > 0

    p=\frac{x}{\sqrt{1-\frac{y^2}{q^2}}}=\frac{x}{\sqrt{\frac{q^2-y^2}{q^2}}} =\frac{x}{\frac{\sqrt{q^2-y^2}}{|q|}}=\frac{|q|x}{\sqrt{q^2-y^2}}
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  5. #5
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    Got it!

    What a relief, thanks Guys.
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