log9 (4) + log3(x) = 3 solve for x

by this I mean log base 9 (4) etc

The different bases makes this harder for me.

This is my (incorrect) attempt

log3(x) + log3(4) = 3

-------

log3(9)

log3(x) + log3(4/9) = 3

log3(4/9) = log(4/9) / log(3) = -0.35

log3(x) = 3 -- 0.35 = 3.35

3^3.35 = x = 39.66 which is incorrect.

Where did I go wrong and how do I solve this?

Angus