log9 (4) + log3(x) = 3 solve for x
by this I mean log base 9 (4) etc
The different bases makes this harder for me.
This is my (incorrect) attempt
log3(x) + log3(4) = 3
-------
log3(9)
log3(x) + log3(4/9) = 3
log3(4/9) = log(4/9) / log(3) = -0.35
log3(x) = 3 -- 0.35 = 3.35
3^3.35 = x = 39.66 which is incorrect.
Where did I go wrong and how do I solve this?
Angus
Your second equation confused me for a moment. It didn't print out the way you wanted it to. Here it is, just for clarity:
You applied your log rules incorrectly in the next line.
But note that . What can you do with this?
The rest of the method is correct, but unless you have any conflicting instructions, I'd solve it exactly...ie leave it in terms of log3(4). (Which you can actually simplify a bit.) There is no need to use a calculator on this one.
-Dan