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Math Help - Simultaneous Exponential Equation Problem

  1. #1
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    May 2011
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    Simultaneous Exponential Equation Problem

    Solve the simultaneous equations:

    64({4}^{y}) = {16}^{x}
    {3}^{y} = 4({3}^{x - 2}) - 1

    The answers are:

    x = 1, y = 1
    x = 2, y = 1

    Thanks in advance.
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  2. #2
    Super Member
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    Jun 2009
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    You can write the first equation as
    4^3*4^y = 4^2x.
    From that you will get the value of y in-terms of x.
    Substitute this value of y in the second equation. Solve the quadratics and find the values of e^x. From that get the required result.
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