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Math Help - Simplifying fractions.

  1. #1
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    Simplifying fractions.

    so if i have the equation (4/3a)+[3/(3a+1)]=-2 should my LCD be 3a(3a+1) or just 3a+1? if so how would I multiply it out?
    Last edited by mr fantastic; May 1st 2011 at 07:51 PM. Reason: Re-titled.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by thedroid View Post
    so if i have the equation (4/3a)+[3/(3a+1)]=-2 should my LCD be 3a(3a+1) or just 3a+1? if so how would I multiply it out?
    \frac{4}{3a} + \frac{3}{3a + 1} = -2

    \frac{4}{3a} \cdot (3a)(3a + 1) + \frac{3}{3a + 1} \cdot (3a)(3a + 1) = -2 \cdot (3a)(3a + 1)

    4(3a + 1) + 3(3a) = -6a(3a + 1)

    Can you finish from here?

    -Dan
    Last edited by topsquark; May 1st 2011 at 05:15 PM.
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    okay then I just cancel out factors? like the (3a+1) in the numerator and denominator in the first part?
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    Forum Admin topsquark's Avatar
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    Quote Originally Posted by thedroid View Post
    okay then I just cancel out factors? like the (3a+1) in the numerator and denominator in the first part?
    I'm an idiot.

    I have corrected my previous post. I plead temporary insanity.

    -Dan
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    okay i got thus far: 7/(3a)(3a+1)=-6a/(3a) how would I solve for a though?
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  6. #6
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by thedroid View Post
    okay i got thus far: 7/(3a)(3a+1)=-6a/(3a) how would I solve for a though?
    I don't know if you've had a chance to see my correction yet.
    4(3a + 1) + 3(3a) = -6a(3a + 1)

    12a + 4 + 9a = -18a^2 - 6a

    18a^2 + 27a + 4 = 0

    -Dan
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