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Math Help - Solving equations involving rational functions of linears.

  1. #1
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    Exclamation Solving equations involving rational functions of linears.

    i have 4 problems that my dad sent me. /=fraction ^=exponent
    1. 2y/y-3=-1/y
    so far i got
    2y^2=-y+3


    2. x/2=3x+8/x
    i got
    x^2=6x+16
    then i dont know what to do next?

    3. x-2/x+6= x/2
    so far
    2x-4=x^2+6

    4. y+2/-y=2/y+3
    I DONT KNOW WHAT TO DO FOR THIS ONE?!


    My questions on proportions.

    1. is it possible for a portion to have two different answers for the same variable?

    2. Is it true you cant add percents unless same?

    Someone help
    Last edited by mr fantastic; May 1st 2011 at 01:17 PM. Reason: Re-titled.
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  2. #2
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    Quote Originally Posted by adit17 View Post
    i have 4 problems that my dad sent me. /=fraction ^=exponent
    1. 2y/y-3=-1/y
    so far i got
    2y^2=-y+3
    What's your dad got to do with this; your math teacher?
    And why call there "proportions"?

    To start, your equation needs a set of brackets:
    2y / (y - 3) = -1 / y

    Your 2y^2 = -y + 3 is correct; go 1 step further:
    2y^2 + y - 3 = 0

    Now solve that for y, by factoring or the quadratic formula.
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  3. #3
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    Quote Originally Posted by adit17 View Post
    i have 4 problems that my dad sent me. /=fraction ^=exponent
    1. 2y/y-3=-1/y
    so far i got
    2y^2=-y+3


    2. x/2=3x+8/x
    i got
    x^2=6x+16
    then i dont know what to do next?

    3. x-2/x+6= x/2
    so far
    2x-4=x^2+6

    4. y+2/-y=2/y+3
    I DONT KNOW WHAT TO DO FOR THIS ONE?!


    My questions on proportions.

    1. is it possible for a portion to have two different answers for the same variable?

    2. Is it true you cant add percents unless same?

    Someone help
    Ask your dad to give you some hints.
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  4. #4
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    1. is it possible for a portion to have two different answers for the same variable?
    As wilmer said your terminology seems a bit unusual. The equations you posted all involve fractions (portions?), but can be re-arranged into quadratic equations. Quadratic equations can have up to 2 solutions.

    for example: x= 1/x has two solutions: x=1, x=-1. You could have got this by rearranging to get x^2 = 1


    4. y+2/-y=2/y+3
    to avoid ambiguity, I assume this is


    for this one, try multiplying both sides by (y+3)(y), then expand the brackets on both sides to get a standard quadratic equation
    Last edited by SpringFan25; May 1st 2011 at 02:53 PM.
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