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Math Help - Throw me some Formulars to work out

  1. #1
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    Throw me some Formulars to work out

    Everyone has been great so far with all the help ive needed. I decided to get a book that starts from the ground up on algebra and read upwards, could someone throw me some formulas to work out, or point me to any websites that host some questions, such as:

    x(3-y) x 6y(y/(34/x)) .........

    Thats just random, but im learning about exponents and how to work out formulas at the moment, the book only provides a few test questions.

    Also, the Order of Operations, does it work the same in programming languages such as Javascript and PHP, although they are web languages, that what im working with at the moment.

    Thanks all, the helps been great I hope one day i can offer help around here to people in my boat, i plan on sticking around (not sure if thats good or bad news for you guys, im sure you will 'beat me with the cane' if i become an annoyance with questions).

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    Quote Originally Posted by JJ07 View Post
    Everyone has been great so far with all the help ive needed. I decided to get a book that starts from the ground up on algebra and read upwards, could someone throw me some formulas to work out, or point me to any websites that host some questions, such as:

    x(3-y) x 6y(y/(34/x)) .........

    Thats just random, but im learning about exponents and how to work out formulas at the moment, the book only provides a few test questions.

    Also, the Order of Operations, does it work the same in programming languages such as Javascript and PHP, although they are web languages, that what im working with at the moment.

    Thanks all, the helps been great I hope one day i can offer help around here to people in my boat, i plan on sticking around (not sure if thats good or bad news for you guys, im sure you will 'beat me with the cane' if i become an annoyance with questions).

    You know, when I was learning this stuff I'd go into one of the classrooms after school and would just starting writing down random stuff like:
    \frac{\left ( (a^3b)^{-3}cd^2 \right ) ^4}{(a^{-2}b^2)^{-2}}
    and simplify it. Actually, the problems I would were longer and far more complicated. But I just made them up, simplified them, checked them as best as I could, erased it, and wrote up another one. Yeah, I'm a geek. But it worked very well.

    -Dan
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by JJ07 View Post
    Also, the Order of Operations, does it work the same in programming languages such as Javascript and PHP, although they are web languages, that what im working with at the moment.
    As to order of operations, it's pretty much standard. But when in doubt, use parentheses to make it do what you want done first.

    -Dan
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  4. #4
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    Dan geeks are good, my friends called me one at school, i decided to hate math due to peer pressure, i wish i would have carried on now.

    But im working toward geek status, im good at Javascript, PHP and General web design and development, people call me a geek, but your not a geek till your math is up to scratch, lol.

    Cheers.

    Id invent my own, but i dont know how i would check them, oh well ill give it a bash.
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by JJ07 View Post
    Id invent my own, but i dont know how i would check them, oh well ill give it a bash.
    That's part of the process, too. If you have to check a problem that you yourself made up then you are forced to do a better job checking it to make sure you did it right. It helps build confidence.

    -Dan
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  6. #6
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    Dan i will give it a go now.

    Just to confirm:

    x = 4
    y = 9

    5x * y3 = 5(5) * (9)3 = (5 * 5) * (9 * 3) = (25) * (27) = 675

    But what if i want to specify say a year: 19xy

    x = 8
    y = 4

    2007 - 19xy

    I dont want it to end up as 19 * x * y

    2007 - 19xy = 2007 - 1984 = 23

    2007 - 19xy = 2007 - 19(8)(4) = 2007 - 19 * 8 * 4 = 2007 - 608 = 1399

    With the parenthesis means multiply, without them they are just number concatenated to the end of '19'.

    Sorry if im being buggy.
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  7. #7
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by JJ07 View Post
    Dan i will give it a go now.

    Just to confirm:

    x = 4
    y = 9

    5x * y3 = 5(5) * (9)3 = (5 * 5) * (9 * 3) = (25) * (27) = 675

    But what if i want to specify say a year: 19xy

    x = 8
    y = 4

    2007 - 19xy

    I dont want it to end up as 19 * x * y

    2007 - 19xy = 2007 - 1984 = 23

    2007 - 19xy = 2007 - 19(8)(4) = 2007 - 19 * 8 * 4 = 2007 - 608 = 1399

    With the parenthesis means multiply, without them they are just number concatenated to the end of '19'.

    Sorry if im being buggy.
    I've seen a number of "year" problems. In type you have 19xy, in "mathspeak" you have 1900 + 10x + y.

    -Dan
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