N= N0/dn

First, I multiplied both sides bydn:dn = N0/N

Then I took the log of both sides:n log d = log(N0/N)

Finally, I divided both sides by log d:n = log(N0/N)/log d

Does this look legit?

I was thinking of using the division log rule to manipulate it further:n = log(N0/N)-log d

Is this correct?

Thanks,

~CC