2 * (0.1)^(x+1) = 25
First divide both sides by 2.
(0.1)^(x+1) = 25/2
Now take logs of both sides
Sorry I am getting errors with latex so ill post in text form, I am getting an answer but I do not think it is right hopefully someone can tell me where I went wrong.
2 * (0.1)^(x+1) = 25
to clarify 2 times 0.1 to the power of x +1 equals 25
I got :
2 * x + 1 * log 0.1 = 25
2 * x * log 0.1 = 24
x * log 0.1 = 12
x = 12 / log 0.1
x = -12
Any input would be appreciated. Thanks
Hello, maca404!
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QUOTE
2*(0.1)^{x+1} .= .25
I got: .2 * x + 1 * log 0.1 .= .25
. . Wow ... This is really wrong!
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We have: . . .2(0.1)^{x+1} .= .25
Divide by 2: . .(0.1)^{x+1} .= .12.5
Take logs: .log(0.1)^{x+1} .= .log(12.5)
. . . . . . . . . . (x+1)log(0.1) .= .log(12.5)
. . . . . . . . . . . . . . . . . . . . . . . log(12.5)
. . . . . . . . . . . . . . . . x + 1 .= .----------
. . . . . . . . . . . . . . . . . . . . . . . .log(0.1)
. . . . . . . . . . . . . . . . . . . . . . . log(12.5)
. . . . . . . . . . . . . . . . . . . x .= .---------- - 1
. . . . . . . . . . . . . . . . . . . . . . . .log(0.1)