hi, Find a in terms of b, given that log3(a b2) = 5 how do you sole this? please help, thanks!
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Originally Posted by [nuthing] hi, Find a in terms of b, given that log3(a b2) = 5 how do you sole this? please help, thanks! From basic log rules: log3(a b2) = log3(a) + log3(b2) = log3(a) + 2log3(b). Use it.
Originally Posted by [nuthing] hi, Find a in terms of b, given that log3(a b2) = 5 how do you solve this? please help, thanks! If the "3" is the base of the logarithm, then you just slide it over to the other side to get (whatever's in brackets)=3^5 Then use basic algebra to get "a" in terms of "b".
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