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Math Help - how to solve this: 9-[(3-2)-8]

  1. #1
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    how to solve this: 9-[(3-2)-8]

    i can't get the right answer for this question.

    9-[(3-2)-8]

    the answer is 16 but i have no idea why it is 16

    this is what i am doing.

    i am doing in the parentheses first (3-2) which is 1
    then i change it around 9-(-1)-8 ===> 9+ (-1) +(-8) which is 0
    the first time i tired i got -17 now i am getting 0
    idk
    Last edited by mr fantastic; April 20th 2011 at 11:31 PM. Reason: Title.
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  2. #2
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    Quote Originally Posted by Candy101 View Post
    i can't get the right answer for this question.

    9-[(3-2)-8]

    the answer is 16 but i have no idea why it is 16

    this is what i am doing.

    i am doing in the parentheses first (3-2) which is 1
    then i change it around 9-(-1)-8 ===> 9+ (-1) +(-8) which is 0 Mr F says: No. The next step is to calculate the number in the square bracket: 1 - 8 = -7.
    the first time i tired i got -17 now i am getting 0
    idk
    Then 9 - [-7] = ....
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  3. #3
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    oohhh..i cant believe i missed that lol i tried for so long! but i got tht part down how is the answer 16?

    dont 9-(-7) 2?
    this is how i did it
    i changed 9-(-7) to ===> 9+(-7) so i got 2?
    i still dont understand how the answer is 16
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  4. #4
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    Quote Originally Posted by Candy101 View Post
    oohhh..i cant believe i missed that lol i tried for so long! but i got tht part down how is the answer 16?

    dont 9-(-7) 2?
    this is how i did it
    i changed 9-(-7) to ===> 9+(-7) so i got 2?
    i still dont understand how the answer is 16
    9 - 7 = 2.

    9 - (-7) = 9 + 7 = 16. Double minus becomes +. Review your arithmetic rules.
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  5. #5
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    ooh thanks!!!!!

    xox
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