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Math Help - Solving second degree equations

  1. #1
    Newbie Bluerabbits's Avatar
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    Exclamation Solving second degree equations

    Im solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides:

    1. 4x^2 = 8x

    2. 8x = 2x^2
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  2. #2
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    Quote Originally Posted by Bluerabbits View Post
    Im solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides:

    1. 4x^2 = 8x

    2. 8x = 2x^2
    Your way of solving the equation isn't wrong but incomplete:

    4x^2 = 8x ===> x^2 = 2x ===> x^2 - 2x = 0 ===> x(x-2) = 0

    A product equals zero if one factor equals zero: x = 0 0r x - 2 = 0

    Solve for x.

    Do the 2nd example similarly.
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Bluerabbits View Post
    Im solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides:

    1. 4x^2 = 8x

    2. 8x = 2x^2
    Either use "completing the square" or the quadratic formula. Show us what you get.

    -Dan
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