I´m solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides: 1. 4x^2 = 8x 2. 8x = 2x^2
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Originally Posted by Bluerabbits I´m solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides: 1. 4x^2 = 8x 2. 8x = 2x^2 Your way of solving the equation isn't wrong but incomplete: 4x^2 = 8x ===> x^2 = 2x ===> x^2 - 2x = 0 ===> x(x-2) = 0 A product equals zero if one factor equals zero: x = 0 0r x - 2 = 0 Solve for x. Do the 2nd example similarly.
Originally Posted by Bluerabbits I´m solving the following second degree equations the wrong way ... I tried to solve the first one by dividing 4 on both sides: 1. 4x^2 = 8x 2. 8x = 2x^2 Either use "completing the square" or the quadratic formula. Show us what you get. -Dan
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