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Math Help - A second degree equation

  1. #1
    Newbie Bluerabbits's Avatar
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    Exclamation A second degree equation [SOLVED]

    I tried to solve the following equation but I got -6 under the radical sign...

    Here´s the equation I tried to solve:

    (y-4)^2 = 64


    Any help perhaps?
    Last edited by Bluerabbits; April 19th 2011 at 11:08 AM.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Bluerabbits View Post
    I tried to solve the following equation but I got -6 under the radical sign...

    Here´s the equation I tried to solve:

    (y-4)^2 = 64


    Any help perhaps?
    Take the square root of both sides:
    y - 4 = +/- sqrt(64)

    y - 4 = +/-8

    Voila! No more radicals!

    -Dan
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  3. #3
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    Or...
    y^2 - 8y + 16 = 64 \Rightarrow y^2 - 8y - 48 = 0
    \Delta=256, y_1 and y_2 = ...
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  4. #4
    Newbie Bluerabbits's Avatar
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    Quote Originally Posted by topsquark View Post
    Take the square root of both sides:
    y - 4 = +/- sqrt(64)

    y - 4 = +/-8

    Voila! No more radicals!


    -Dan

    Thank you!

    answers:

    y1 = 12

    y2 = -4

    - Anika
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