I tried to solve the following equation but I got -6 under the radical sign... Here´s the equation I tried to solve: (y-4)^2 = 64 Any help perhaps?
Last edited by Bluerabbits; Apr 19th 2011 at 11:08 AM.
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Originally Posted by Bluerabbits I tried to solve the following equation but I got -6 under the radical sign... Here´s the equation I tried to solve: (y-4)^2 = 64 Any help perhaps? Take the square root of both sides: y - 4 = +/- sqrt(64) y - 4 = +/-8 Voila! No more radicals! -Dan
Or... - 8y + 16 = 64 - 8y - 48 = 0 =256, and = ...
Originally Posted by topsquark Take the square root of both sides: y - 4 = +/- sqrt(64) y - 4 = +/-8 Voila! No more radicals! -Dan Thank you! answers: y1 = 12 y2 = -4 - Anika
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