Log equation from acoustics.

Hi, I'm doing a diplomamin acoustics and I need to know how to deal with a certain mathematical situation. Without going into too much detail I just need to know how rearrange an equation such as y equals log x plus 1 over x, so that x is the subject. The log is base 10.

Any help would be greatly appreciated.

Tom

You're asking to solve y = log_{10}(x) + 1/x for x? It can't be done.

OK that's good to know, thanks.
Tom

Quote:

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Originally Posted by pitchtwit

Hi, I'm doing a diplomamin acoustics and I need to know how to deal with a certain mathematical situation. Without going into too much detail I just need to know how rearrange an equation such as y equals log x plus 1 over x, so that x is the subject. The log is base 10.

Any help would be greatly appreciated.

Tom

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Do you mean y = log((x+1)/x) or y = log(x) + (1/x).

Your lack of clarity has possbily led to you being given the wrong answer.

Or y = log(x + (1/x)) ???

My apologies, it was supposed to be y = log(x) + (1/x)