7, 17, 41
Hello, qwertyuiop!
If t(n+1) = 2t(n) + t(n-1) . and t(1) = 1, t(2) = 3,
what are the next 3 numbers of the sequence?
It seems that you don't understand that the equation says:
. . "A term is equal to twice the preceding term, plus the term before that."
We have: .t(1) = 1
. . . . . . . .t(2) = 3
Then: .t(3) .= .2(3) + 1 .= .7
Then: .t(4) .= .2(7) + 3 .= .17
Then: .t(5) .= .2(17) + 7 .= .41
Get it?