Let .
Substituting into your Quartic gives
.
Expanding this out and collecting like terms will give you the required form.
this one is giving me some trouble. I am not sure what method to use.
I figure first expand the equation which gives me quartic form.
but after that I am stuck. I don't think I can factor with the methods I know. I tried a few ways. and substitution seems to fail to get anywhere.
the solution is which does expand to the the same quartic as above. I have NO idea how to do this.
Hello, skoker!
We have: .(3x + 2) [(x-1)^3 + 3(x-1)^2 + 2(x-1) + 1]
. . . . . = . [3(x-1) + 5] [(x-1)^3 + 3(x-1)^2 + 2(x-1) + 1]
. . . . . = . 3(x-1)^4 + 9(x-1)^3 + 6(x-1)^2 + 3(x-1)
. . . . . . . . . . . . . . + 5(x-1)^3 + 15(x-1)^2 + 10(x-1) + 5
. . . . . = . 3(x-1)^4 + 14(x-1)^3 + 21(x-1)^2 + 13(x-1) + 5