A line with slope 2 intersects a line with slope 6 at the point (40,30). What is the
distance between the x-intercepts of these lines? How is the answer 10?
Here is the way I would do it.
y=2x+b
30=2(40)+b
30=80+b
-50=b
y=2x-50
then y=6x+b
30=6(40)+b
30=240+b
-210=b
y=6x-210
we have y=2x-5 and y=6x-210
0=2x-5 and 0=6x-210
5=2x 210=6x
x=5/2 x=35
total answer of 32.5 but it is supposed to be 10 what am i doing wrong?
Hello, sundance240!
A silly error . . .
Here is the way I would do it.
y .= .2x + b
. . 30 .= .2(40) + b . → . b = -50
. . y .= .2x - 50
y .= .6x + b
. . 30 .= .6(40) + b . → . b =-210
. . y .= .6x - 210
. . . . . . . . . . . . . . . ↓
We have: .y .= .2x - 5 . . . y .= .6x - 210