Hi Guys,
I need a little help with the algebra in this inequality. I have made a bit of mess of it.
Given,
Deduce, that n must exceed,
Thanks.
EDIT: Not sure why the latex code is giving an error. I checked it in MikTex and it works fine?
Hi Guys,
I need a little help with the algebra in this inequality. I have made a bit of mess of it.
Given,
Deduce, that n must exceed,
Thanks.
EDIT: Not sure why the latex code is giving an error. I checked it in MikTex and it works fine?
There seem to be problems with LaTeX in MHF after yesterday's shutdown.
I got to the required conclusion under a couple of assumptions, but I have 100^2 instead of 100. First, if 1 - x^{n+1} > 0 and 100^2 + k > 0, then the initial inequality can be solved for x^{n+1} to get
x^{n+1} < k / (100^2 + k).
Then if x > 0, we have
(1 / x)^{n+1} > (100^2 + k) / k.
Taking log of both sides and dividing by log(1 / x) (which requires that log(1 / x) > 0, i.e., 1 / x > 1, i.e., x < 1, which accords with 1 - x^{n+1} > 0 above), you get the required inequality.