Hi All;
I have two solutions to the problem 9x^2 + 2sqrt3y - 3x^2sqrt3y they are
6x^2 + sqrt3y and 6x^2sqrt3y.
Please let me know which is right and how we got there.
Thanks.
Do you know how many search engines there are on the net? Give a link or something, will you?
However, no matter what the link is the only thing that can be done with this is
$\displaystyle 9x^2 + 2 \sqrt{3y} - 3x^2 \sqrt{3y} = 9x^2 + (2 - 3x^2)\sqrt{3y}$
or
$\displaystyle 9x^2 + 2 \sqrt{3y} - 3x^2 \sqrt{3y} = 3x^2(3 - \sqrt{3y} ) + 2 \sqrt{3y}$
-Dan
http://http://www.germanna.edu/tutor..._exponents.pdf
heres the link.
The problem is $\displaystyle 4x\sqrt{12x^2y}+\sqrt{3x^4y}-x^2\sqrt{3y}$
I know how the got their answer. BUT it is wrong.
If you look at that expression we see that $\displaystyle y\ge 0$ but $\displaystyle x$ can be any real number.
Now why is it incorrect? Let $\displaystyle x=-3~\&~y=3$ the given expression evaluates to $\displaystyle 270$.
BUT $\displaystyle 6x^2\sqrt{3y}=162$. To be equal the values must be the same.
Here is the mistake. They said $\displaystyle 4x\sqrt{12x^2y}=8x^2\sqrt{3y}$. BUT IT DOES NOT.
This is what is correct: $\displaystyle 4x\sqrt{12x^2y}=8x|x|\sqrt{3y}$.