Hi All,

Simplify the following expression

$\displaystyle

\dfrac

{

(b+c)^{\frac{-3}{8}} -

(b-c)^{\frac{-3}{8}}

}

{(b^2 - c^2)^{\frac{5}{8}}

}

$

I am unclear on how to proceed with this problem. Your help is much appreciated. Thanks.

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- Apr 9th 2011, 06:11 AMmathguy80Not sure how to rationalize the denominator
Hi All,

Simplify the following expression

$\displaystyle

\dfrac

{

(b+c)^{\frac{-3}{8}} -

(b-c)^{\frac{-3}{8}}

}

{(b^2 - c^2)^{\frac{5}{8}}

}

$

I am unclear on how to proceed with this problem. Your help is much appreciated. Thanks. - Apr 9th 2011, 06:21 AMProve It
Try multiplying top and bottom by $\displaystyle \displaystyle \left(b^2 - c^2\right)^{\frac{3}{8}}$.

- Apr 9th 2011, 08:03 AMmathguy80
Ah cool! I see. So Rationalizing here is to try to get the power of the denominator = 1. That works out, Thanks!