hi guys,

is there anyway to simplify this equation in such a way that r will only occur on the left hand side of the equation:

$\displaystyle

r = \frac{1}{sin\theta \sqrt{2\pi}} e^{-\frac{(rcos\theta)^2}{2}}

$

I've only gone as far as taking the natural logarithm of both sides:

$\displaystyle

ln r = -ln(sin\theta\sqrt{2\pi}) - \frac{r^2cos^2\theta}{2}

$

After this, I don't really know how I can isolate r. Any ideas?