Hey, sorry having troubles re-organising this eqn.

Could someone please help me reorganise this eqn so that it is in the form where

L = ......................

Thanks

$\displaystyle

D(n)=L\times 1.005301^n - p\frac{1-1.005301^{n-1}}{1-1.005301}

$,

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- Aug 13th 2007, 01:50 AMtom_asianReorganising eqn so it is in the form of L =
Hey, sorry having troubles re-organising this eqn.

Could someone please help me reorganise this eqn so that it is in the form where

L = ......................

Thanks

$\displaystyle

D(n)=L\times 1.005301^n - p\frac{1-1.005301^{n-1}}{1-1.005301}

$, - Aug 13th 2007, 02:17 AMticbol
Finding L is like isolating L on the lefthand side (LHS) of the equation.

So you dispose off the negative part of the righthand side (RHS). Transpose it to the LHS.

Then, eliminate the barnacle 1.005301^n by dividing both sides of the new equation by 1.005301^n.

So L is isolated on the RHS.

Then, swap the positions so that the lonely L will be at LHS and the rest will be at the RHS.

Voila!

In my version,

L = [D_n +{p(1 -1.005301)^(n-1) / (1 -1.005301)}] / (1.005301^n)