hi,

i need to work out the co ordinates of two points that the graph of y=2x-1 passes through.

i don't really know how to do this so could somone explain what i have to do please?!?

thanks!

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- April 7th 2011, 11:15 AMandyboy179work out the co ordinates
hi,

i need to work out the co ordinates of two points that the graph of y=2x-1 passes through.

i don't really know how to do this so could somone explain what i have to do please?!?

thanks! - April 7th 2011, 11:55 AMe^(i*pi)
Pick any old values of x and put the corresponding y value in.

For example (0,-1) is a point on the line - April 7th 2011, 11:59 AMandyboy179
oh so would (1, -1) be one aswell?

- April 7th 2011, 12:10 PMTheChaz
- April 7th 2011, 12:11 PMe^(i*pi)
No, what makes you say that?

The equation is a straight line. If you want to use x=1 then it would be - April 7th 2011, 12:15 PMandyboy179
would (-1,0) work?

- April 7th 2011, 12:17 PMe^(i*pi)
- April 7th 2011, 12:18 PMTheChaz
When x = -1,

y = 2x - 1 becomes

y = 2(-1) - 1 =

-2 -1 = -3

S0 (-1, -3) is the point - April 7th 2011, 12:19 PMandyboy179
oh i see now, thanks alot!

- April 7th 2011, 12:32 PMandyboy179
no its -1

- April 7th 2011, 12:42 PMveileen
Uhm, you don't simply search numbers that verify the equation, but take the intersection with the axes (make x=0 and find y, then make y=0 and find x).

- April 7th 2011, 12:47 PMNOX Andrew
That's only necessary to find the x- and y-intercepts. For any two points on the line, any two values of x suffice.

- April 7th 2011, 11:44 PMCaptainBlack
- April 7th 2011, 11:45 PMCaptainBlack
- April 7th 2011, 11:45 PMCaptainBlack