"I figured out that p(-1) = 0 that would mean that x+1 is a factor of this equation." Good, so you have: .
I don't understand what you did in that picture, but from here, in general can be factored: .
~ , for the second bracket x is common factor.
This is the equation that needs to be fully factored. So, from what I see here it would be impossible to factor it normally, since 1 can't be multiplied by 3 or any other number to get 1 other then 1.
I figure this is a good idea to use factor theorem. I figured out that p(-1) =0 that would mean that x+1 is a factor of this equation.
next I did division
I got stuck half way through the division when I reached the (x^2 -1)(x^2-x) I don't think i can subtract 1-x. Not sure where to go from here. any help appreciated.
Your right...I forgot about adding the 0x...thank you though. I kind of feel stupid now..lol
Besides long division you can do this by simple "eye", meaning: just complete the second factor to what you need:
...how did I find the factor ? Well, we need , so we must
multiply . After this we need , and we already have , so we have so
far only , so we need to add ...and etc.
Of course, after this we can continue and etc.