$\displaystyle 2x^3+3x^2-1$

This is the equation that needs to be fully factored. So, from what I see here it would be impossible to factor it normally, since 1 can't be multiplied by 3 or any other number to get 1 other then 1.

I figure this is a good idea to use factor theorem. I figured out that p(-1) =0 that would mean that x+1 is a factor of this equation.

next I did division

I got stuck half way through the division when I reached the (x^2 -1)(x^2-x) I don't think i can subtract 1-x. Not sure where to go from here.

any help appreciated.