Hi All,

I was studying logarithms today, and came across this problem. Need a hint on how to proceed.

$\displaystyle 2^{4x} - 3^{3x} + 4^{2x} = 0$

I simplified it down to,

$\displaystyle \frac{2^{4x}}{3^{3x}} = \frac{1}{2}$

How do I proceed further? Thanks!