The position vectors a, b, c of points A, B, C satisfy c = (3b-1)/(3-1). What is the ratio AC:CB? and where would C be located on a line with A and B (between A and B, next to B or next to C)?

Not sure how to do this - help would be appreciated :)

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- Apr 5th 2011, 04:48 PMbrumby_3Vectors - finding the ratio
The position vectors a, b, c of points A, B, C satisfy c = (3b-1)/(3-1). What is the ratio AC:CB? and where would C be located on a line with A and B (between A and B, next to B or next to C)?

Not sure how to do this - help would be appreciated :) - Apr 5th 2011, 05:56 PMsurjective
Hello,

So you mean that $\displaystyle \vec{c}=\frac{3\vec{b}-1}{3-1}$. If this is true then it does not make sense. How would you subtract a number from a vector?