How do I find x for
$\displaystyle 1 = x(x-6)$
$\displaystyle x(x-6)=1$
Expand the brackets by multiplying everything inside the bracket with everything outside the bracket term by term to obtain:
$\displaystyle x^2-6x=1$ Then rearrange:
$\displaystyle x^2-6x-1=0$
Which is just a standard solvable quadratic, but it won't factorize, so you'll either have to use the formula or complete the square. Can you remember how to do that?