How do I find x for

$\displaystyle 1 = x(x-6)$

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- Apr 5th 2011, 08:32 AMDevi09Solving for x
How do I find x for

$\displaystyle 1 = x(x-6)$ - Apr 5th 2011, 08:41 AMQuacky
$\displaystyle x(x-6)=1$

Expand the brackets by multiplying everything inside the bracket with everything outside the bracket term by term to obtain:

$\displaystyle x^2-6x=1$ Then rearrange:

$\displaystyle x^2-6x-1=0$

Which is just a standard solvable quadratic, but it won't factorize, so you'll either have to use the formula or complete the square. Can you remember how to do that?(Wink) - Apr 5th 2011, 08:45 AMDevi09
Yeh. Plug in the values and you get x= 6.1623 and x= -0.16228

And if you were to solve for 1 = (x-3)(x+1)

you just expand, set the equation to 0 and find the x's right? - Apr 5th 2011, 08:48 AMQuacky
- Apr 5th 2011, 07:15 PMProve It