# Algebra question involving speed and distance

• Apr 5th 2011, 07:52 AM
Nightgal
Algebra question involving speed and distance
Thomas was walking to the store at a brisk 4.5 mph pace. When he reached the store he met his friend Blake and together they walked back at a 3.0 mph pace. Thomas's trip was a total of 1 hour.

A how long did it take him to walk to the store?

B. What is the distance to the store?

Can someone please show me how go set these up? It's been 8 years si nce I last did algebra and I am finding out I have forgotten a lot. (Thinking)
• Apr 5th 2011, 08:31 AM
HallsofIvy
Call the time took him to walk to the store, in hours, $t_1$. Since "distance= time*speed" the distance to the store is $d= 4.1t_1$ miles. Call the time it took them to walk back from the store, in hours, $t_2$. Then we also have $d= .0t_2$. Of course, the distance to the store is the same as the distance back so we have $d= 4.1t_1= 3.0t_2$. We also are told that the total time is $t_1+ t_2= 1$.
• Apr 5th 2011, 08:33 AM
Nightgal
Where do you get the 4.1 from?
• Apr 5th 2011, 09:34 AM
topsquark
Quote:

Originally Posted by Nightgal
Where do you get the 4.1 from?

It was a typo. d = 4.5*t

-Dan