The standard form has integer coefficients.
Hi, I'm new here! I'm having an issue with this problem in my homework. I need to find the equation of each line and put it in standard form.
The points I have are (-7, -4) and (0,6).
So I used the y2-y1 method.
(6-4)
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(0-(-7) and got 10/7. So y= 10/7x + b. Then I found b.
-4 = 10/7(-7) + b
-4 = 10 + b
-6 = b so in slope-intercept form my answer is y= 10/7x - 6.
But i need it in standard form and the tutorials I've found for this say you just need to minus mx from both sides. So I did and I got -10/7x +y = -6. However my book says the answer should be 2x + 7y = -42.
I think I'm not understanding how to convert slope-intercept form to standard form. The other problems in my homework have the same issue.
By the way, I hope I put this in the correct format- sorry if I didn't! Thank you...