Please help me to solve this
cot3a=(cot<3>a - 3cota)/3cot<3>a-1
<> = superscript value
I need to prove above formula.
Thanks
First of all, please use brackets where they're needed. Also, the ^ symbol is the symbol used for superscripts. Either that, or use LaTeX.
Anyway, are you trying to solve
$\displaystyle \displaystyle \cot{3a} = \frac{\cot^3{a} - 3\cot{a}}{3\cot^3a} - 1$
or
$\displaystyle \displaystyle \cot{3a} = \frac{\cot^3{a} - 3\cot{a}}{3\cot^3a - 1}$?