Hi MHF!
I've been having some problems recently with word problems. I'm still not used to English, I guess.
So:
Consider the Integral expression in .
Where and the value of is a rational number for any which satisfies the equation , and in this case the value of is:
I'm sorry if there's any typos in there, I've copied this some time ago.
What "the integral expression in " means?
or maybe ?
Not having a clue on how to start, I've tried to resolve .
Still with and , no luck.
represents many numbers, right? But what number does it actually ask for?
Is and ?
is supposed to be a root
*completely lost*
Thanks :3
The word "integral" has two completely different meanings in English. It can mean something to do with integration, or it can mean something to do with integers.
My guess is that this is an algebra problem, not a calculus problem, and that "the integral expression in " means "a function of whose value is an integer". So forget about integration, and think about integers. As you correctly say, the solutions of the equation are . Plug those values into the expression , and find the value of for which the answer is an integer. In other words, choose so that terms involving cancel out and you are left with an "integral" answer.
I'll have to revive this thread since I'm still having difficulties.
Opalg suggested me to plug the values in the formula.
I'm kind of confused, since the question says this is a value of P and not of x
So what would be right?
or probably
In this case, what would happen to P?
Would it equal zero? Would it equal ?
Both cases, I still get a racional number that is nowhere near
This sqrt3 is really annoying.
Thanks!
This second one.
It must be equal to an integer. It might be 0 but certainly notIn this case, what would happen to P?
Would it equal zero? Would it equal ?
??? No one has said anything about a being equal to -4.Both cases, I still get a racional number that is nowhere near
If what is ? What is ? What is ? What value of a will make that an integer?This sqrt3 is really annoying.
Thanks!
Hi HallsofIvy!
hahah the a=-4 part is the answer!
Sorry If I haven't made myself clear.
Right! = when
=
I'm not sure where you want to get here, sorry.
I'm still not sure about the end of that equation.
It also says that a is a rational number.
This has been omited so far, I'm sorry.
Working on the question we get.
Ok, so if we equal this to zero and square both sides we can get
a^2=73/4
This gives something close to 4.23...
Close enough, but is this conclusive?
We still have to find the value of P when a is in our desired value.
Edit: Can some moderator please move this topic to it's right place?
This looks like but is not a calculus problem.
Okay- but that is not what I get for . For you should have , not what you have.
No, it does not equal 0- only the coefficient of has to be 0 in order that P be an integer.I'm not sure where you want to get here, sorry.
I'm still not sure about the end of that equation.
It also says that a is a rational number.
This has been omited so far, I'm sorry.
Working on the question we get.
Ok, so if we equal this to zero and square both sides we can get
a^2=73/4
This gives something close to 4.23...
Close enough, but is this conclusive?
We still have to find the value of P when a is in our desired value.
Edit: Can some moderator please move this topic to it's right place?
This looks like but is not a calculus problem.
It is, actually!
I left it this way because it is easier to make it disappear in the main question, this is about taste hahah
Later on you have
Which gets to the final
not 2\sqrt{3} as I have mentioned earlier.
No, it does not equal 0- only the coefficient of has to be 0 in order that P be an integer.
OK! I think I get it!
If
This is correct!
I made some trivial mistakes here and there probably because I was lunching when I did this.
Thanks for your help!