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Math Help - Puzzle like algebra question

  1. #1
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    Puzzle like algebra question

    Hey All,

    This one feels a like difficult math puzzle. I have no idea where to start on this one. I tried guessing around on the calculator, but that won't really explain the right approach for such a problem, which is what I am looking for.

    Given the following 7 numbers,

     2, 3, 4, 9, 64, 71, 91

    Find six numbers a, b, c, d, e and f from the list such that,

    a(b + c) = d(e + f)

    The only interesting thing I see here is the numbers 2, 2^{2} = 4, 4^{3} = 64. But no clue as to how this is useful.

    Thanks for all your help.
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  2. #2
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    Quote Originally Posted by mathguy80 View Post
    Hey All,

    This one feels a like difficult math puzzle. I have no idea where to start on this one. I tried guessing around on the calculator, but that won't really explain the right approach for such a problem, which is what I am looking for.

    Given the following 7 numbers,

     2, 3, 4, 9, 64, 71, 91

    Find six numbers a, b, c, d, e and f from the list such that,

    a(b + c) = d(e + f)

    The only interesting thing I see here is the numbers 2, 2^{2} = 4, 4^{3} = 64. But no clue as to how this is useful.

    Thanks for all your help.
    64(2+3)=4(71+9)
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  3. #3
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    64(3 + 2) = 4(71 + 9) ; plus a few rearrangements, like 64(2 + 3)...
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  4. #4
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    Thanks, @earboth and @Wilmer. Turns out paper was better option to figure out the right combination.
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