Originally Posted by

**mathguy80** Hey All,

This problem must be done without the use of a calculator. I am able to guesstimate my way to a close enough answer but need some help to improve this.

If **n ** **<-- typo? Shouldn't that be s?** is the largest square number such that $\displaystyle s \leq n$, find s when

(i) $\displaystyle n = 6.4 \times 10^{3}$

(ii) $\displaystyle n = 6.4 \times 10^{6}$

I got (i) $\displaystyle s = 6400$ easily since its a perfect square,

For (ii) I wrote the number as $\displaystyle 64 \times 10^{4} \times 10$

Then nearest perfect square close to 10 is 9, so $\displaystyle s \approx 8^{2} \times 100^{2} \times 3^{2}$

From there I figured that the number is between $\displaystyle 2400^{2}$ and further got to $\displaystyle s = 2500^{2} = 6250000$

The problem is that the required answer is $\displaystyle 6395841$ and the weight-age is only 1 mark. Using the calculator suggests this is the exactly correct answer.

But since this is a non-calculator use problem, leads me to believe I am missing an obvious/simpler/faster way of getting there. What am I missing?

Thanks again for all your help.