Thread: S=2LW+2LH+2WH for H

I know how to solve for H, but I'm not understanding how we get there.

S = 2LW + 2LH + 2WH

2LW + 2LH + 2WH = S

2LH + 2WH = S - 2LW it appears that there are 2 H's

H = S - 2LW / (2L + 2W) but here we only arrive with one

2LH + 2WH = S - 2LW

H(2L + 2W) = s- 2LW

H = (S - 2LW)/(2L + 2W)

Originally Posted by rtblue

2LH + 2WH = S - 2LW

H(2L + 2W) = s- 2LW

H = (S - 2LW)/(2L + 2W)

Excellent explanation - thank you very much.