I know how to solve for H, but I'm not understanding how we get there. S = 2LW + 2LH + 2WH 2LW + 2LH + 2WH = S 2LH + 2WH = S - 2LW it appears that there are 2 H's H = S - 2LW / (2L + 2W) but here we only arrive with one

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2LH + 2WH = S - 2LW H(2L + 2W) = s- 2LW H = (S - 2LW)/(2L + 2W)

Originally Posted by rtblue 2LH + 2WH = S - 2LW H(2L + 2W) = s- 2LW H = (S - 2LW)/(2L + 2W) Excellent explanation - thank you very much.

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