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Math Help - formula explanation

  1. #1
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    formula explanation

    Can you please tell me in dummy terms what is going on with the GCF parts in this equation and how -2HW got moved to the right side of the equation. Was that part of the GCF or was it just subtracted from both sides of the equation?

    thanks

    S=2LW+2LH+2WH

    Since L is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
    2LW+2LH+2WH=S

    Factor out the GCF of 2L from each term in the polynomial.
    2L(W)+2L(H)=-2HW+S

    Factor out the GCF of 2L from 2LW+2HL.
    2L(W+H)=-2HW+S

    Divide each term in the equation by (W+H).
    (2L(W+H))/(W+H)=-(2HW)/(W+H)+(S)/(W+H)

    Simplify the left-hand side of the equation by canceling the common terms.
    2L=-(2HW)/(W+H)+(S)/(W+H)

    Simplify the right-hand side of the equation by simplifying each term.
    2L=(-2HW+S)/(W+H)

    Divide each term in the equation by 2.
    (2L)/(2)=(-2HW+S)/(W+H)/(2)

    Simplify the left-hand side of the equation by canceling the common terms.
    L=(-2HW+S)/(W+H)/(2)

    Simplify the right-hand side of the equation by simplifying each term.
    L=(-2HW+S)/(2(W+H))
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  2. #2
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    Which part exactly are you not sure of?
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  3. #3
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    Quote Originally Posted by hansfordmc View Post
    S = 2LW + 2LH + 2WH
    Don't know what you're asking...or why all that work is shown...
    If you're solving that equation for L, then:

    1: get L terms on one side: 2WL + 2HL = S - 2WH

    2: factor left side: L(2W + 2H) = S - 2WH

    3: divide by 2W + 2H : L = (S - 2WH) / (2W + 2H) ; finished.
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