Can you please tell me in dummy terms what is going on with the GCF parts in this equation and how -2HW got moved to the right side of the equation. Was that part of the GCF or was it just subtracted from both sides of the equation?

thanks

S=2LW+2LH+2WH

Since L is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.

2LW+2LH+2WH=S

Factor out the GCF of 2L from each term in the polynomial.

2L(W)+2L(H)=-2HW+S

Factor out the GCF of 2L from 2LW+2HL.

2L(W+H)=-2HW+S

Divide each term in the equation by (W+H).

(2L(W+H))/(W+H)=-(2HW)/(W+H)+(S)/(W+H)

Simplify the left-hand side of the equation by canceling the common terms.

2L=-(2HW)/(W+H)+(S)/(W+H)

Simplify the right-hand side of the equation by simplifying each term.

2L=(-2HW+S)/(W+H)

Divide each term in the equation by 2.

(2L)/(2)=(-2HW+S)/(W+H)/(2)

Simplify the left-hand side of the equation by canceling the common terms.

L=(-2HW+S)/(W+H)/(2)

Simplify the right-hand side of the equation by simplifying each term.

L=(-2HW+S)/(2(W+H))