# transposing a sqrt

• Mar 30th 2011, 09:00 AM
robhare
transposing a sqrt
Goodday
I have the following equation , but i'm trying to find Q.
How would i transpose this to put Q on the other end of the =

d = sqrt (4*Q/pi*v)
• Mar 30th 2011, 09:12 AM
Quacky
Quote:

Originally Posted by robhare
Goodday
I have the following equation , but i'm trying to find Q.
How would i transpose this to put Q on the other end of the =

d = sqrt (4*Q/pi*v)

$\displaystyle d=\sqrt{\dfrac{4Q}{v\pi}}$?

If so, then $\displaystyle d^2=\dfrac{4Q}{v\pi}$ (I've squared both sides)

And $\displaystyle d^2v\pi=4Q$ (Timesed both sides by $\displaystyle v\pi$)

So $\displaystyle Q=\dfrac{d^2v\pi}{4}$ (Divided both sides by 4)
• Mar 30th 2011, 10:05 PM
robhare
thanks , perfect
• Apr 24th 2011, 02:48 AM
robhare
Hi , help one more time please .
How would the equation look if i wanted to isolate v on the other side of the = .
thanks
rob
• Apr 24th 2011, 06:15 AM
HallsofIvy
Go back to $\displaystyle d^2v\pi= 4Q$
v is not yet "isolated" because it is multiplied by $\displaystyle v\pi$. So do the opposite: divide both sides by $\displaystyle v\pi$.