I have the equation: 16^n < 8^(n+1) And need to solve for n. What I did: 8^(4/3) = 16 n < (4/3)(n+1) n < 4/3n + 4/3 3n < 4n + 4 -n < 4 n > 4 But, in the back of the book the answer is n < 3. What did I do wrong?
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Originally Posted by thyrgle I have the equation: 16^n < 8^(n+1) And need to solve for n. What I did: 8^(4/3) = 16 n < (4/3)(n+1) n < 4/3n + 4/3 3n < 4n + 4 -n < 4 n > 4 But, in the back of the book the answer is n < 3. What did I do wrong? Your claim is correct: . So that implies that the inequality can be written as: So this is true when and this will give you the conclusion that's desired ( ). I hope this clarifies things.
Ok thanks, I switched them around, my brain is dead today.
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