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Math Help - Logarithms

  1. #1
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    Logarithms

    Hey guys, I was just wondering how I would solve these 2 problems.

    4^x = 10^(x+1)
    I wrote this in logarithmic form and got
    xlog4=(x+1)log10, but I'm confused what to do since there is an x on both sides.

    45e^(.457p) = 95
    Don't even know how to approach this one.

    Thanks for your help.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Jubbly View Post
    4^x = 10^(x+1)
    xlog4=(x+1)log10, but I'm confused what to do since there is an x on both sides.
    x \cdot log(4) = x \cdot log(10) + log(10)

    x \cdot log(4) - x \cdot log(10) = log(10)

    Now factor the LHS

    -Dan
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Jubbly View Post
    45e^(.457p) = 95
    \displaystyle 45 e^{.457p} = 95

    \displaystyle e^{.457p} = \frac{95}{45}

    Can you take it from here?

    -Dan
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  4. #4
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    Thanks so much, but I don't know what to do for this and what does LHS stand for?
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  5. #5
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    Quote Originally Posted by Jubbly View Post
    Thanks so much, but I don't know what to do for this and what does LHS stand for?
    LHS ... Left-Hand Side of the equation

    x\log{4} - x\log{10} = \log{10}

    x(\log{4} - \log{10}) = \log{10}

    finish it.
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  6. #6
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    Quote Originally Posted by Jubbly View Post
    Thanks so much, but I don't know what to do for this and what does LHS stand for?
    LHS means Left Hand Side; take out the x : x[log(4) - log(10)]

    You don't know what to do for WHAT?
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