Logarithms

**Jubbly** · March 28th 2011, 03:40 PM

Hey guys, I was just wondering how I would solve these 2 problems.

4^x = 10^(x+1)
I wrote this in logarithmic form and got
xlog4=(x+1)log10, but I'm confused what to do since there is an x on both sides.

45e^(.457p) = 95
Don't even know how to approach this one.

Thanks for your help.

**topsquark** · March 28th 2011, 04:34 PM

Originally Posted by Jubbly

4^x = 10^(x+1)
xlog4=(x+1)log10, but I'm confused what to do since there is an x on both sides.

$x \cdot log(4) = x \cdot log(10) + log(10)$

$x \cdot log(4) - x \cdot log(10) = log(10)$

Now factor the LHS

-Dan

**topsquark** · March 28th 2011, 04:36 PM

Originally Posted by Jubbly

45e^(.457p) = 95

$\displaystyle 45 e^{.457p} = 95$

$\displaystyle e^{.457p} = \frac{95}{45}$

Can you take it from here?

-Dan

**Jubbly** · March 28th 2011, 04:44 PM

Thanks so much, but I don't know what to do for this and what does LHS stand for?

**skeeter** · March 28th 2011, 05:15 PM

Originally Posted by Jubbly

Thanks so much, but I don't know what to do for this and what does LHS stand for?

LHS ... Left-Hand Side of the equation

$x\log{4} - x\log{10} = \log{10}$

$x(\log{4} - \log{10}) = \log{10}$

finish it.

**Wilmer** · March 28th 2011, 05:19 PM

Originally Posted by Jubbly

Thanks so much, but I don't know what to do for this and what does LHS stand for?

LHS means Left Hand Side; take out the x : x[log(4) - log(10)]

You don't know what to do for WHAT?

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