. It's a very important bracket there, as you wrote it +1 is not in the exponent. Also
Nonetheless you're on the right track:
x is now a factor of both terms on the LHS. Can you finish?
edit: if the answer has in then recall
Hello, I have the following equation:
5^x = 4^x+1
I am confident the first two steps are:
(using common log)
a) log5^x = log 4^x+1
b) xlog5 = x+1log 4
However I can not figure out to finish the problem.
Can someone please help ?
Thanks kindly
. It's a very important bracket there, as you wrote it +1 is not in the exponent. Also
Nonetheless you're on the right track:
x is now a factor of both terms on the LHS. Can you finish?
edit: if the answer has in then recall